9x^2+21x-44=0

Solution for 9x^2+21x-44=0 equation:

9x^2+21x-44=0

a = 9; b = 21; c = -44;
Δ = b2-4ac
Δ = 212-4·9·(-44)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-45}{2*9}=\frac{-66}{18}
=-3+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+45}{2*9}=\frac{24}{18}
=1+1/3
$